zip_entry_filesize
If you want to get the real name of the file without the directory name, you can just use the function basename() as the follow:
<?
$zip_dir = "./import/";
$zip = zip_open($zip_dir."import.zip");
if ($zip) {
while ($zip_entry = zip_read($zip)) {
$file = basename(zip_entry_name($zip_entry));
$fp = fopen($zip_dir.basename($file), "w+");
if (zip_entry_open($zip, $zip_entry, "r")) {
$buf = zip_entry_read($zip_entry, zip_entry_filesize($zip_entry));
zip_entry_close($zip_entry);
}
fwrite($fp, $buf);
fclose($fp);
echo "The file ".$file." was extracted to dir ".$zip_dir."\n<br>";
}
zip_close($zip);
}
?>
Thefore you can extract files without concern with the directory that is set inside the zip source.
Remember to give write permission (w) on that directory.
Hello from Brazil.
Leandro
zip_entry_name
(PHP 4 >= 4.0.7, PHP 5 >= 5.2.0, PECL zip:1.0-1.9.0)
zip_entry_name — Retorna o nome do arquivo
Descrição
string zip_entry_name
( resource $zip_entry
)
Retorna o nome do arquivo especificado.
Valor Retornado
O nome do diretório de entrada.
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User Contributed Noteszip_entry_name
leandro_dealmeida at hotmail dot com
27-Sep-2002 06:21
27-Sep-2002 06:21