@ ben at onshop dot co dot uk
Your example is the slowest possible way to do it.
The whole idea behind using ctype_alnum is that it is much faster than a regexp.
If you have to use regexp, at least use PCRE, not POSIX.
ctype_alnum
(PHP 4 >= 4.0.4, PHP 5)
ctype_alnum — Verifica se os caracteres são alfanuméricos
Descrição
bool ctype_alnum
( string $text
)
Verifica se todos os caracteres na string fornecida, text , é alfanumérico. No padrão C locale letras são [A-Za-z].
Parâmetros
- text
-
A string a ser testada.
Valor Retornado
Retorna TRUE se todos caracteres em text são letra ou dígito, FALSE caso contrário.
Exemplos
Exemplo #1 Um exemplo da ctype_alnum() (usando o locale padrão)
<?php
$strings = array('AbCd1zyZ9', 'foo!#$bar');
foreach ($strings as $testcase) {
if (ctype_alnum($testcase)) {
echo "The string $testcase consists of all letters or digits.\n";
} else {
echo "The string $testcase does not consist of all letters or digits.\n";
}
}
?>
O exemplo acima irá imprimir:
The string AbCd1zyZ9 consists of all letters or digits. The string foo!#$bar does not consist of all letters or digits.
ctype_alnum
kostromin at gmail com
26-Feb-2008 11:24
26-Feb-2008 11:24
ben at onshop dot co dot uk
13-Jan-2008 04:03
13-Jan-2008 04:03
Oops, above example should read:
if(eregi('[^a-zA-Z0-9_]', $str)){
$msg = 'Please enter an alphanumeric value';
)
ben at onshop dot co dot uk
13-Jan-2008 02:26
13-Jan-2008 02:26
An alternative if you need to accept underscores as well:
$str = 'user_name';
if(!eregi('[^a-zA-Z0-9_]', $str)){
$msg = 'Please enter an alphanumeric value';
)
