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ctype_alpha> <Funções da Ctype
Last updated: Fri, 22 Aug 2008

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ctype_alnum

(PHP 4 >= 4.0.4, PHP 5)

ctype_alnumVerifica se os caracteres são alfanuméricos

Descrição

bool ctype_alnum ( string $text )

Verifica se todos os caracteres na string fornecida, text , é alfanumérico. No padrão C locale letras são [A-Za-z].

Parâmetros

text

A string a ser testada.

Valor Retornado

Retorna TRUE se todos caracteres em text são letra ou dígito, FALSE caso contrário.

Exemplos

Exemplo #1 Um exemplo da ctype_alnum() (usando o locale padrão)

<?php
$strings 
= array('AbCd1zyZ9''foo!#$bar');
foreach (
$strings as $testcase) {
    if (
ctype_alnum($testcase)) {
        echo 
"The string $testcase consists of all letters or digits.\n";
    } else {
        echo 
"The string $testcase does not consist of all letters or digits.\n";
    }
}
?>

O exemplo acima irá imprimir:

The string AbCd1zyZ9 consists of all letters or digits.
The string foo!#$bar does not consist of all letters or digits.



ctype_alpha> <Funções da Ctype
Last updated: Fri, 22 Aug 2008
 
add a note add a note User Contributed Notes
ctype_alnum
kostromin at gmail com
26-Feb-2008 11:24
@ ben at onshop dot co dot uk

Your example is the slowest possible way to do it.
The whole idea behind using ctype_alnum is that it is much faster than a regexp.
If you have to use regexp, at least use PCRE, not POSIX.
ben at onshop dot co dot uk
13-Jan-2008 04:03
Oops, above example should read:

if(eregi('[^a-zA-Z0-9_]', $str)){
 $msg = 'Please enter an alphanumeric value';
)
ben at onshop dot co dot uk
13-Jan-2008 02:26
An alternative if you need to accept underscores as well:

$str = 'user_name';

if(!eregi('[^a-zA-Z0-9_]', $str)){
 $msg = 'Please enter an alphanumeric value';
)

ctype_alpha> <Funções da Ctype
Last updated: Fri, 22 Aug 2008
 
 
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