mysql_fetch_row

(PHP 4, PHP 5, PECL mysql:1.0)

mysql_fetch_row — 結果を添字配列として取得する

説明

array mysql_fetch_row ( resource $result )

取得された行に対応する配列を返し、内部のデータポインタを前に進めます。

パラメータ

result: 評価された結果リソース。この結果は、mysql_query() のコールにより得られたものです。

返り値

取得された行に対応する文字列の配列を返します。もう行がない場合は、 FALSE を返します。

mysql_fetch_row()は、指定した結果 ID が指す結果から 1 行分のデータを取得します。各結果カラムは、オフセット 0 から始まる配列に格納されます。

例

例1 mysql_fetch_row() で行を取得する


<?php
$result = mysql_query("SELECT id,email FROM people WHERE id = '42'");
if (!$result) {
    echo 'Could not run query: ' . mysql_error();
    exit;
}
$row = mysql_fetch_row($result);

echo $row[0]; // 42
echo $row[1]; // 'email' の値
?>

注意

注意: この関数は、 NULL フィールドに PHPの NULL 値を設定します。

参考

mysql_field_flags

mysql_fetch_object

Last updated: Fri, 10 Oct 2008

add a note User Contributed Notes
mysql_fetch_row

larkitetto at gmail dot com
22-Feb-2008 12:29


sry :) note now fixed:



<?php

$esi=mysql_list_tables($db);$ris=mysql_fetch_row($esi);

//example: $db has >= 1 tabs

echo var_dump($ris);

//echoes only array(1). solution:

while($ris=mysql_fetch_row($esi)) echo $ris[0];

/*debug:

$ris=array("1st_tab"); ... $ris=array("n_tab");$ris=false;*/

while ($ris[]=mysql_fetch_row($esi));

//debug:$ris=array(array("1st_tab"), ... array("n_tab"));

echo $ris[n][0];//echo:"n_tab"

echo $ris[0][n];//echo:array | null

?>



hope it helps

ryhan_balboa at yahoo dot com
16-Nov-2007 06:23


The following are the basic codes to get a specific row from the mysql db into a $row variable:



 

$query = "SELECT * FROM table"; 

$result = mysql_query($query); 

$row = mysql_fetch_row($result);



And $row[0], $row[1] ... $row[n] are used to access those field values. 



Does anyone know how I can add a new field to $row, so that the field count increases from n to n+1?



I have tried treating $row like an array, and tried array_push function, but didn't work.



Thanks.

m dot s at programmers-online dot net
17-Nov-2005 10:56


The following function to read all data out of a mysql-resultset, is may be faster than Rafaels solution:



<?

function mysql_fetch_all($result) {

   while($row=mysql_fetch_array($result)) {

       $return[] = $row;

   }

   return $return;

}

?>

mysql at polyzing dot com
13-Jul-2003 12:05


It is probably worth pointing out that the array elements will actually be of type string, OR NULL if the field is null in the database.



Thus, either use a double equal comparison to look for empty or null



Or, use a triple equal comparison to be able to distinguish the two cases



e.g.



if ($field === '') echo "Empty, not NULL\n";



if ($field === NULL) echo "NULL\n";



if ($field == '') echo "Empty or NULL\n";

michael and then an at sign wassupy.com
08-Apr-2003 09:09


to print an array, simply use print_r(array name)



like this:

    $myrow = mysql_fetch_row($result);

echo "<pre>";

print_r($myrow);

echo "</pre>";



this will output the array in a readable form, with the index, too. Don't forget the 'pre' tags or the output will be on a single line.

a at simongrant dot org
06-Feb-2002 02:10


Maybe worth pointing out that all the fields returned by this (and other?) calls are returned with type string. This had me puzzled for quite some time.

add a note

mysql_field_flags

mysql_fetch_object

Last updated: Fri, 10 Oct 2008