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Предопределенные переменные> <Манипуляции с типами
Last updated: Fri, 09 May 2008

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Переменные

Содержание

Основы

Переменные в PHP представлены знаком доллара с последующим именем переменной. Имя переменной чувствительно к регистру.

Имена переменных соответствуют тем же правилам, что и остальные наименования в PHP. Правильное имя переменной должно начинаться с буквы или символа подчеркивания с последующими в любом количестве буквами, цифрами или символами подчеркивания Это можно отобразить регулярным выражением: '[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*'

Замечание: Для наших целей буквы здесь - это a-z, A-Z, и ASCII-символы со 127 по 255 (0x7f-0xff).

<?php
$var 
"Bob";
$Var "Joe";
echo 
"$var, $Var";      // выведет "Bob, Joe"

$4site 'not yet';     // неверно; начинается с цифры
$_4site 'not yet';    // верно; начинается с символа подчеркивания
$tдyte 'mansikka';    // верно; 'д' это (Дополнительный) ASCII 228.
?>

В PHP 3 переменные всегда присваивались по значению. То есть, когда вы присваиваете выражение переменной, все значение оригинального выражения копируется в эту переменную. Это означает, к примеру, что после присвоения одной переменной значения другой, изменение одной из них не влияет на значение другой. Дополнительную информацию об этом способе присвоения смотрите в разделе Выражения.

PHP 4 предлагает иной способ присвоения значений переменным: присвоение по ссылке. Это означает, что новая переменная просто ссылается (иначе говоря, "становится псевдонимом" или "указывает") на оригинальную переменную. Изменения в одной переменной отражаются на оригинале, и наоборот. Это также означает, что копирования не происходит; таким образом, присвоение осуществляется быстрее. Однако, любое увеличение скорости будет хорошо заметно только в сжатых циклах или при присвоении больших массивов или объектов.

Для присвоения по ссылке, просто добавьте амперсанд (&) к началу имени присваиваемой (исходной) переменной. Например, следующий фрагмент кода дважды выводит 'My name is Bob':

<?php
$foo 
'Bob';              // Присваивает $foo значение 'Bob'
$bar = &$foo;              // Ссылка на $foo через $bar.
$bar "My name is $bar";  // Изменение $bar...
echo $bar;
echo 
$foo;                 // меняет и $foo.
?>

Важно отметить, что по ссылке могут быть присвоены только именованные переменные.

<?php
$foo 
25;
$bar = &$foo;      // Это верное присвоение.
$bar = &(24 7);  // Неверно; ссылка на неименованное выражение.

function test()
{
   return 
25;
}

$bar = &test();    // Неверно.
?>



add a note add a note User Contributed Notes
Переменные
(rot13) yrvsrevx [at] jro [dot] qr
15-Feb-2008 04:00
err, the "($old = $var)" could also evaluate to false. Adding a "|| true" would make this overall to crude, I guess. It's better to leave it out of the expression.
(rot13) yrvsrevx [at] jro [dot] qr
15-Feb-2008 01:22
@cgorbit: This does not work, because "=" has a lower operator precedence than "||". The expression "($var = $old || true)" assigns true to $var. I corrected this and further shortened the function by putting "$old = $var" into the expression, too. :)
Note the parentheses that are necessary because of the operator precedence of "=" and "&&".

function var_name(&$var, $scope=0)
{
    if (($old = $var) && ($key = array_search($var = 'unique'.rand().'value', !$scope ? $GLOBALS : $scope)) && (($var = $old) || true)) return $key;
}
cgorbit
05-Jan-2008 12:34
<?php
function var_name(&$var, $scope=0)
{
   
$old = $var;
    if ((
$key = array_search($var = 'unique'.rand().'value', !$scope ? $GLOBALS : $scope)) && ($var = $old || true)) return $key
}
?>

Because $var may casts to false
alexandre at nospam dot gaigalas dot net
07-Jul-2007 06:13
Here's a simple solution for retrieving the variable name, based on the lucas (http://www.php.net/manual/en/language.variables.php#49997) solution, but shorter, just two lines =)

<?php
function var_name(&$var, $scope=0)
{
   
$old = $var;
    if ((
$key = array_search($var = 'unique'.rand().'value', !$scope ? $GLOBALS : $scope)) && $var = $old) return $key
}
?>
jsb17 at cornell dot edu
20-Feb-2007 05:48
As an addendum to David's 10-Nov-2005 posting, remember that curly braces literally mean "evaluate what's inside the curly braces" so, you can squeeze the variable variable creation into one line, like this:

<?php
 
${"title_default_" . $title} = "selected";
?>

and then, for example:

<?php
  $title_select
= <<<END
    <select name="title">
      <option>Select</option>
      <option $title_default_Mr  value="Mr">Mr</option>
      <option $title_default_Ms  value="Ms">Ms</option>
      <option $title_default_Mrs value="Mrs">Mrs</option>
      <option $title_default_Dr  value="Dr">Dr</option>
    </select>
END;
?>
code at slater dot fr
25-Jan-2007 11:10
Here's a pair of functions to encode/decode any string to be a valid php and javascript variable name.

<?php

function label_encode($txt) {
 
 
// add Z to the begining to avoid that the resulting
  // label is a javascript keyword or it starts with a
  // number
 
$txt = 'Z'.$txt;
 
 
// encode as urlencoded data
 
$txt = rawurlencode($txt);
 
 
// replace illegal characters
 
$illegal = array('%', '-', '.');
 
$ok = array('é', 'è', 'à');
 
$txt = str_replace($illegal,$ok, $txt);
 
  return
$txt;
}

function
label_decode($txt) {
 
 
// replace illegal characters
 
$illegal = array('%', '-', '.');
 
$ok = array('é', 'è', 'à');
 
$txt = str_replace($ok, $illegal, $txt);
 
 
// unencode
 
$txt = rawurldecode($txt);
 
 
// remove the leading Z and return
 
return substr($txt,1);
}

?>
whoami
28-Dec-2006 07:14
what is so simple and flexible about these variable..? They're all the same thing -.-"
$var = whatever;

in fact is more complicated than:

String HelloWorld = hello;
giunta dot gaetano at sea-aeroportimilano dot it
04-Aug-2006 10:44
With php 5.1.4 (and maybe earlier?) take care about not using $this as a variable name, even when in the global scope or inside a plain function: the engine will prevent assigning any value to it...
molnaromatic at gmail dot com
20-May-2006 02:44
Simple sample and variables and html "templates":
The PHP code:
variables.php:
<?php
$SYSN
["title"] = "This is Magic!";
$SYSN["HEADLINE"] = "Ez magyarul van"; // This is hungarian
$SYSN["FEAR"] = "Bell in my heart";
?>

index.php:
<?php
include("variables.php");
include(
"template.html");
?>

The template:
template.html

<html>
<head><title><?=$SYSN["title"]?></title></head>
<body>
<H1><?=$SYSN["HEADLINE"]?></H1>
<p><?=$SYSN["FEAR"]?></p>
</body>
</html>
This is simple, quick and very flexibile
warhog at warhog dot net
28-Dec-2005 08:11
> Variable names follow the same rules as other labels in PHP. A valid variable name starts with a letter or underscore, followed by any number of letters, numbers, or underscores. As a regular expression, it would be expressed thus: '[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*'

..is not quite true. You can, in fact, only declare variables having a name like this if you use the syntax <?php $varname = "naks naks"; ?>.. but in fact a variable can have moreless any name that is a string... e.g. if you look at an array you can have
<?php
$arr
[''];
$arr['8'];
$arr['-my-element-is-so-pretty-useless-'];
?>
.. by accessing the variables-namespace via {} you can have the same functinalities for all variables, e.g.

<?php ${''} = "my empty variable"; ?>

is a valid expression and the variable having the empty string as name will have the value "my empty variable".

read the chapter on "variable variables" for further information.
Mike at ImmortalSoFar dot com
25-Nov-2005 11:03
References and "return" can be flakey:

<?php
//  This only returns a copy, despite the dereferencing in the function definition
function &GetLogin ()
{
    return
$_SESSION['Login'];
}

//  This gives a syntax error
function &GetLogin ()
{
    return &
$_SESSION['Login'];
}

//  This works
function &GetLogin ()
{
   
$ret = &$_SESSION['Login'];
    return
$ret;
}
?>
david at removethisbit dot futuresbright dot com
10-Nov-2005 10:25
When using variable variables this is invalid:

$my_variable_{$type}_name = true;

to get around this do something like:

$n="my_variable_{$type}_name";
${$n} = true;

(or $$n - I tend to use curly brackets out of habit as it helps t reduce bugs ...)
ludvig dot ericson at gmail dot com
13-Oct-2005 01:33
On the previous note:

This is due to how evaluation works. PHP will think of it as:

$a = whatever $b = $c is
$b = whatever $c = 1 is

... because an expression is equal to what it returns.

Therefore $c = 1 returns 1, making $b = $c same as $b = 1, which makes $b 1, which makes $a be $b, which is 1.

$a = ($b = $c = 1) + 2;
Will have $a be 3 while $b and $c is 1.

Hope that clears something up.
Chris Hester
31-Aug-2005 02:09
Variables can also be assigned together.

<?php
$a
= $b = $c = 1;
echo
$a.$b.$c;
?>

This outputs 111.
Mike Fotes
09-Jul-2005 08:46
In conditional assignment of variables, be careful because the strings may take over the value of the variable if you do something like this:

<?php
$condition
= true;

// Outputs " <-- That should say test"
echo "test" . ($condition) ? " <-- That should say test" : "";
?>

You will need to enclose the conditional statement and assignments in parenthesis to have it work correctly:

<?php
$condition
= true;

// Outputs "test <-- That should say test"
echo "test" . (($condition) ? " <-- That should say test " : "");
?>
josh at PraxisStudios dot com
17-May-2005 10:06
As with echo, you can define a variable like this:

<?php

$text
= <<<END

<table>
    <tr>
        <td>
             $outputdata
        </td>
     </tr>
</table>

END;

?>

The closing END; must be on a line by itself (no whitespace).
user at host dot network
02-May-2005 02:17
pay attention using spaces, dots and parenthesis in case kinda like..
$var=($number>0)?1.'parse error':0.'here too';
the correct form is..
$var=($number>0)?1 .'parse error':0 .'here too';
or
$var=($number>0)?(1).'parse error':(0).'here too';
or
$var = ($number > 0) ? 1 . 'parse error' : 0 . 'here too';
etc..
i think that's why the parser read 1. and 0. like decimal numbers not correctly written, point of fact
$var=$number>0?1.0.'parse error':0.0.'here too';
seems to work correctly..
david at rayninfo dot co dot uk
26-Apr-2005 01:01
When constructing strings from text and variables you can use curly braces to "demarcate" variables from any surrounding text where, for whatever reason, you cannot use a space eg:

$str="Hi my name is ${bold}$name bla-bla";

which AFAIK is the same as

$str="Hi my name is {$bold}$name bla-bla";

zzapper
mike at go dot online dot pt
07-Apr-2005 06:18
In addition to what jospape at hotmail dot com and ringo78 at xs4all dot nl wrote, here's the sintax for arrays:

<?php
//considering 2 arrays
$foo1 = array ("a", "b", "c");
$foo2 = array ("d", "e", "f");

//and 2 variables that hold integers
$num = 1;
$cell = 2;

echo ${
foo.$num}[$cell]; // outputs "c"

$num = 2;
$cell = 0;

echo ${
foo.$num}[$cell]; // outputs "d"
?>
lucas dot karisny at linuxmail dot org
15-Feb-2005 01:42
Here's a function to get the name of a given variable.  Explanation and examples below.

<?php
 
function vname(&$var, $scope=false, $prefix='unique', $suffix='value')
  {
    if(
$scope) $vals = $scope;
    else     
$vals = $GLOBALS;
   
$old = $var;
   
$var = $new = $prefix.rand().$suffix;
   
$vname = FALSE;
    foreach(
$vals as $key => $val) {
      if(
$val === $new) $vname = $key;
    }
   
$var = $old;
    return
$vname;
  }
?>

Explanation:

The problem with figuring out what value is what key in that variables scope is that several variables might have the same value.  To remedy this, the variable is passed by reference and its value is then modified to a random value to make sure there will be a unique match.  Then we loop through the scope the variable is contained in and when there is a match of our modified value, we can grab the correct key.

Examples:

1.  Use of a variable contained in the global scope (default):
<?php
  $my_global_variable
= "My global string.";
  echo
vname($my_global_variable); // Outputs:  my_global_variable
?>

2.  Use of a local variable:
<?php
 
function my_local_func()
  {
   
$my_local_variable = "My local string.";
    return
vname($my_local_variable, get_defined_vars());
  }
  echo
my_local_func(); // Outputs: my_local_variable
?>

3.  Use of an object property:
<?php
 
class myclass
 
{
    public function
__constructor()
    {
     
$this->my_object_property = "My object property  string.";
    }
  }
 
$obj = new myclass;
  echo
vname($obj->my_object_property, $obj); // Outputs: my_object_property
?>
jospape at hotmail dot com
05-Feb-2005 08:45
$id = 2;
$cube_2 = "Test";

echo ${cube_.$id};

// will output: Test
ringo78 at xs4all dot nl
14-Jan-2005 09:27
<?
// I am beginning to like curly braces.
// I hope this helps for you work with them
$filename0="k";
$filename1="kl";
$filename2="klm";
 
$i=0;
for (
$varname = sprintf("filename%d",$i);   isset  ( ${$varname} ) ;   $varname = sprintf("filename%d", $i)  )  {
    echo
"${$varname} <br>";
   
$varname = sprintf("filename%d",$i);
   
$i++;
}
?>
Carel Solomon
07-Jan-2005 12:02
You can also construct a variable name by concatenating two different variables, such as:

<?

$arg
= "foo";
$val = "bar";

//${$arg$val} = "in valid";     // Invalid
${$arg . $val} = "working";

echo
$foobar;     // "working";
//echo $arg$val;         // Invalid
//echo ${$arg$val};     // Invalid
echo ${$arg . $val};    // "working"

?>

Carel
raja shahed at christine nothdurfter dot com
25-May-2004 07:58
<?php
error_reporting
(E_ALL);

$name = "Christine_Nothdurfter";
// not Christine Nothdurfter
// you are not allowed to leave a space inside a variable name ;)
$$name = "'s students of Tyrolean language ";

print
" $name{$$name}<br>";
print 
"$name$Christine_Nothdurfter";
// same
?>
webmaster at surrealwebs dot com
09-Mar-2004 09:31
OK how about a practicle use for this:

You have a session variable such as:
$_SESSION["foo"] = "bar"
and you want to reference it to change it alot throughout the program instaed of typing the whole thing over and over just type this:

$sess =& $_SESSION
$sess['foo'] = bar;

echo $sess['foo'] // returns bar
echo $_SESSION["foo"] // also returns bar
just saves alot of time in the long run

also try $get = $HTTP_GET_VARS
or $post = $HTTP_POST_VARS
webmaster at daersys dot net
20-Jan-2004 05:15
In reference to "remco at clickbizz dot nl"'s note I would like to add that you don't necessarily have to escape the dollar-sign before a variable if you want to output it's name.

You can use single quotes instead of double quotes, too.

For instance:

<?php
$var
= "test";

echo
"$var"; // Will output the string "test"

echo "\$var"; // Will output the string "$var"

echo '$var'; // Will do the exact same thing as the previous line
?>

Why?
Well, the reason for this is that the PHP Parser will not attempt to parse strings encapsulated in single quotes (as opposed to strings within double quotes) and therefore outputs exactly what it's being fed with :)

To output the value of a variable within a single-quote-encapsulated string you'll have to use something along the lines of the following code:

<?php
$var
= 'test';
/*
Using single quotes here seeing as I don't need the parser to actually parse the content of this variable but merely treat it as an ordinary string
*/

echo '$var = "' . $var . '"';
/*
Will output:
$var = "test"
*/
?>

HTH
- Daerion
unleaded at nospam dot unleadedonline dot net
15-Jan-2003 03:37
References are great if you want to point to a variable which you don't quite know the value yet ;)

eg:

$error_msg = &$messages['login_error']; // Create a reference

$messages['login_error'] = 'test'; // Then later on set the referenced value

echo $error_msg; // echo the 'referenced value'

The output will be:

test

 
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