date_timezone_set
Hi ! I've had a specific need to find out if a day is the day when a country switch to winter/spring times , aka loosing one hour or getting one hour compared to the real time .. This works in europe , but i don't know about other regulations or countries , so be warned. The switch to "spring time" is always on the last saturday of march. The switch to winter time is always last saturday of october. Hope it helps !
use it like this :
<?php
if(checkSwitchToWinterTime('20081025'){
echo 'today we switch to winter time' ;
}
function checkSwitchToWinterTime($day){
//day is yyyymmdd
$y =substr($day,0,4);
$m = substr($day,4,2);
$d = substr($day,6,2);
// if it is a saturday of october, check if it's the last one
if(date("D-m", mktime(0, 0, 0, $m, $d, $y))=="Sat-10"){ ;
if((date("m", mktime(0, 0, 0, $m, $d, $y))) != (date("m", mktime(0, 0, 0, $m, $d+7, $y)))) {
return true;
}
return;
}
return;
}
function checkSwitchToSpringTime($day){
//day is yyyymmdd
$y =substr($day,0,4);
$m = substr($day,4,2);
$d = substr($day,6,2);
// if it is a saturday of march, check if it's the last one
if(date("D-m", mktime(0, 0, 0, $m, $d, $y))=="Sat-03"){ ;
if((date("m", mktime(0, 0, 0, $m, $d, $y))) != (date("m", mktime(0, 0, 0, $m, $d+7, $y)))) {
return true;
}
return;
}
return;
}
?>
date
(PHP 4, PHP 5)
date — Formatta una data o orario locale
Descrizione
string date
( string $formato
[, int $
timestamp
] )
Restituisce una stringa formattata in accordo con il formato della stringa usato nell' intero timestamp o nell'attuale orario locale se timestamp non è assegnato.
Nota: Il valido intervallo del timestamp è abitualmente da Fri, 13 Dec 1901 20:45:54 GMT a Tue, 19 Jan 2038 03:14:07 GMT. (Queste date corrispondono al valore minimo e al massimo per un intero segnato a 32-bit.)
Per generare un timestamp da una stringa rappresentante la data, devi sapere usare strtotime(). In aggiunta, dei databases hanno funzioni che convertono i loro formati di data in timestamps (come la funzione di MySQL, UNIX_TIMESTAMP).
I seguenti caratteri sono utilizzati nella stringa formato:
- a - "am" o "pm"
- A - "AM" o "PM"
- B - Swatch Internet time
- d - giorno del mese, 2 cifre senza tralasciare gli zero; i.e. "01" a "31"
- D - giorno della settimana, testuale, 3 lettere; i.e. "Fri"
- F - mese, testuale, long; i.e. "January"
- g - ora, formato a 12-ore senza eventuali zero; i.e. "1" a "12"
- G - ora, formato a 24-ore senza eventuali zero; i.e. "0" a "23"
- h - ora, formato a 12-ore; i.e. "01" a "12"
- H - ora, formato a 24-ore; i.e. "00" a "23"
- i - minuti; i.e. "00" a "59"
- I (i grande) - "1" se c'è l'ora legale, "0" altrimenti.
- j - giorno del mese senza eventuali zero; i.e. "1" a "31"
- l ('L' piccola) - giorno della settimana, testuale, long; i.e. "Friday"
- L - valore booleano per stabilire se è un anno bisestile; i.e. "0" o "1"
- m - mese; i.e. "01" a "12"
- M - mese, testuale, 3 lettere; i.e. "Jan"
- n - mese senza eventuali zero; i.e. "1" a "12"
- O - Differenza in ore dal fuso orario Greenwich; i.e. "+0200"
- r - Data formattata RFC 822; i.e. "Thu, 21 Dec 2000 16:01:07 +0200" (aggiunto nel PHP 4.0.4)
- s - secondi; i.e. "00" a "59"
- S - Suffisso ordinale Inglese per i giorni del mese, 2 caratteri; i.e. "th", "nd"
- t - numero di giorni del mese dato; i.e. "28" a "31"
- T - Fuso orario di questo computer; i.e. "MDT"
- U - secondi dall'epoca since the epoch
- w - giorno della settimana, numerico, i.e. "0" (Domenica) a "6" (Sabato)
- W - ISO-8601 Numero della settimana dell'anno, le settimane iniziano il lunedì (aggiunto in PHP 4.1.0) (Sabato)
- Y - anno, 4 cifre; i.e. "1999"
- y - anno, 2 cifre; i.e. "99"
- z - giorno dell'anno; i.e. "0" a "365"
- Z - Fuso orario in secondi (i.e. "-43200" a "43200"). Il fuso orario ad ovest dell'UTC è sempre negativo, e per quelli ad est è sempre positivo.
Example #1 Esempio di date()
echo date ("l dS of F Y h:i:s A");
echo "July 1, 2000 is on a " . date ("l", mktime(0,0,0,7,1,2000));
Puoi utilizzare un carattere utilizzabile nella stringa del formato come carattere normale facendolo semplicemente precedere dal carattere di escape, il backslash. Se il carattere con un backslash è ancora una sequenza speciale, devi inserire di nuovo il carattere di escape per il backslash.
Example #2 Caratteri di escape in date()
echo date("l \\t\h\e jS"); // scrive qualcosa tipo 'Saturday the 8th'
È possibile usare date() e mktime() assieme per cercare delle date nel futuro o nel passato.
Example #3 Esempio di date() e mktime()
$tomorrow = mktime (0,0,0,date("m") ,date("d")+1,date("Y"));
$lastmonth = mktime (0,0,0,date("m")-1,date("d"), date("Y"));
$nextyear = mktime (0,0,0,date("m"), date("d"), date("Y")+1);
Nota: Questo può essere più affidabile della semplice addizione e sottrazione del numero di secondi in un giorno o mese a un timestamp a causa del daylight savings time.
Alcuni esempi della formattazione di date(). Nota che puoi scrivere qualsiasi altro carattere senza escape, il quale attualmente non dovrebbe produrre risultati indesiderati, ma altri caratteri potrebbero essere assegnati come caratteri della stringa di formattazione nelle prossime versioni del PHP. Quando si utilizza il carattere di escape, assicurati di usare un singolo apice per prevenire che caratteri come \n facciano iniziare una nuova linea.
Example #4 Formattazione con date()
/* Today is March 10th, 2001, 5:16:18 pm */
$today = date("F j, Y, g:i a"); // March 10, 2001, 5:16 pm
$today = date("m.d.y"); // 03.10.01
$today = date("j, n, Y"); // 10, 3, 2001
$today = date("Ymd"); // 20010310
$today = date('h-i-s, j-m-y, it is w Day z '); // 05-16-17, 10-03-01, 1631 1618 6 Fripm01
$today = date('\i\t \i\s \t\h\e jS \d\a\y.'); // It is the 10th day.
$today = date("D M j G:i:s T Y"); // Sat Mar 10 15:16:08 MST 2001
$today = date('H:m:s \m \i\s\ \m\o\n\t\h'); // 17:03:17 m is month
$today = date("H:i:s"); // 17:16:17
Per formattare le date in lingue diverse dall'inglese, dovresti usare le funzioni setlocale() e strftime().
Guarda anche getlastmod(), gmdate(), mktime(), strftime() e time().
add a note
User Contributed Notesdate
bintjes at gmail dot com
10-Oct-2008 03:08
10-Oct-2008 03:08
adityabhai [at] gmail [dot] com
07-Oct-2008 11:56
07-Oct-2008 11:56
Aditya Bhatt (adityabhai [at] gmail [dot] com):
I have one date, and i want the next day of that date:
<?php
echo date("D F d Y",strtotime("+1 days")); // Same applies for months e.g. "+1 months"
?>
I have one date, and i want the previous day of that date:
<?php
echo date("D F d Y",strtotime("-1 days")); // Same applies for months e.g. "-1 months"
?>
adityabhai [at] gmail [dot] com
07-Oct-2008 11:52
07-Oct-2008 11:52
Aditya Bhatt (adityabhai [at] gmail [dot] com):
I have the current date & time, with me or any other date for which i want to check the month.
I want to display the next month using date function, it can be very helpful and a simple way to do this:
<?php
echo date('F j, Y, g:i a');
echo '<br />';
echo date('F j, Y, g:i a', strtotime('+1 month')); // Here you can change '+1 month' to n number of months you required in some of your calculation.
?>
Kenneth Kin Lum
03-Oct-2008 12:52
03-Oct-2008 12:52
date(DATE_RFC822) and date(DATE_RFC2822) both work. note that RFC 822 is obsoleted by RFC 2822. The main difference is the year being 08 in RFC 822 and is 2008 in RFC 2822.
To use date(DATE_RFC2822), a short form is date('r').
cservant at videotron dot ca
26-Sep-2008 05:14
26-Sep-2008 05:14
This is a code to convert RSS pubDate to a timestamp.
A timestamp is an INT which is faster and easier to sort than VARCHAR.
<?php
function pubDate_to_timestamp($time){
//Thu, 21 Aug 2008 01:14:36 PDT
//=> date("D, j M Y H:i:s T");
$time = explode(' ', $time);
$chrono = explode(':', $time[4]);
$month = array('Jan' => 1, 'Feb' => 2, 'Mar' => 3, 'Apr' => 4, 'May' => 5,
'Jun' => 6, 'Jul' => 7, 'Aug' => 8, 'Sep' => 9, 'Oct' => 10,
'Nov' => 11, 'Dec' => 12);
$mktime = mktime($chrono[0], $chrono[1], $chrono[2], $month[$time[2]], $time[1], $time[3], $time[5]);
return $mktime;
}
?>
nick at nick-web dot co dot uk
25-Sep-2008 05:48
25-Sep-2008 05:48
RE: wulf dot kaiser at mpimf-heidelberg dot mpg dot de code to work out fridays in a month. I noticed one small error. It looks like the
<?php
if ($givenMonth != '12') {
$nextGivenMonth = "1";
$nextGivenYear = $givenYear + 1;}
?>
block was setting every month to 1 because it was not equal to 12. I changed that to <?php if ($givenMonth == '12') { ?>and now all is fine!
Now - to refine it so that it only shows Fridays on the 5th or after, until the 4th of the next month.. Damm UK tax stuff!
=)
N
Landito
25-Sep-2008 01:44
25-Sep-2008 01:44
Changing the Timezones.
Europe/Germany to USA/East and change it back
I needed the actual time of NY. ;)
<?PHP
putenv("TZ=EST5EDT");
$date = date("Ymd-H:i:s");
putenv("TZ=MEZ-1MESZ");
?>
Anonymous
25-Sep-2008 01:35
25-Sep-2008 01:35
MySQL 5 will accept ISO_8601 encoded time, so it is acceptable to use date(ISO_8601)
dave dot artur at gmail dot com
24-Sep-2008 05:28
24-Sep-2008 05:28
I see a lot of solutions to date math / difference / subtraction issues, here's something I found works and is much simpler than some of the other things here. Apparently converting date values to a string allows you to apply arithmatic to them.
------------------------------
<?php
// Load the length of a song in seconds
$songLength = $emerge->getSongValue($sID, "songLength");
// Find when 1 frame started playing the song and convert that value to a string
// This works when pulling a datetime value from SQL
$songStart = (string)($emerge->getListItem("eID", $eID, "startTime"));
$songStart = (string)strtotime($songStart);
// The above is slightly roundabout, but seems to be the trick to getting PHP to stop treating variables like date values and doing weird math.
// Find when the current frame was loaded.
// This works when just using PHP date/time values
$loadTime = (string)date("U");
// Calculate the difference in seconds and convert to a value for a refresh entry.
$timeDiff = $loadTime - $songStart;
$length = (($songLength - $timeDiff) * 1000);
?>
jonathancnewcomb at msn dot com
20-Sep-2008 10:11
20-Sep-2008 10:11
The following is a function that will convert Unix Epoch to date format string.
<?PHP
// Function by Jonathan C Newcomb
function unix_to_date($date_format, $unix_epoch){
// Get current server GMT
$gmt = date('P');
$gmt_split = explode(':', $gmt);
$gmt_offset = $gmt_split[0];
$ret = date($date_format, mktime(0 + ($gmt_offset),0, $unix_epoch, 1, 1, 1970));
return $ret;
}
?>
domi at lab-9 dot com
16-Sep-2008 09:14
16-Sep-2008 09:14
<?php
#
# retrieve total count of weeks in a year
#
# param: (int) $year the year in which you wanna get the week count; if not int (for example from date('Y') it is automatically casted
#
# --- NOTE:
# seen a lot of stuff around but nothing as fast;
# mktime() is a very performant operation and the loop
# is executed max 13 times
#
#
# see: http://www.php.net/mktime
# see: http://www.php.net/intval
#
function total_weeks($year) {
if(!is_int($year)) $year = intval($year);
$i=31;
while(date('w', mktime(23,59,59,12,$i,$year)) != 0) $i--;
return date('W', mktime(23,59,59,12,$i,$year));
}
?>
Anonymous
12-Sep-2008 03:01
12-Sep-2008 03:01
Correct format for a MySQL DATETIME column is
<?php $mysqltime = date ("Y-m-d H:i:s", $phptime); ?>
Cortexd
27-Aug-2008 08:47
27-Aug-2008 08:47
a date function supporting the milliseconds format character
<?php
function udate($format, $utimestamp = null)
{
if (is_null($utimestamp))
$utimestamp = microtime(true);
$timestamp = floor($utimestamp);
$milliseconds = round(($utimestamp - $timestamp) * 1000000);
return date(preg_replace('`(?<!\\\\)u`', $milliseconds, $format), $timestamp);
}
echo udate('H:i:s.u'); // 19:40:56.78128
echo udate('H:i:s.u', 654532123.04546); // 16:28:43.45460
?>
pdubbb1 at gmail dot com
26-Aug-2008 02:32
26-Aug-2008 02:32
here is the simpliest way to get the start and end date of the week;
<?php
$sdate=date('c',strtotime(date('Y')."W".date('W')."0"));
$edate=date('c',strtotime(date('Y')."W".date('W')."7"));
?>
the format is for the string in strtotime is;
2008W200
this stands for year - 2008, constant never changes - W, week number of the year - 20, day of the week - 0 for sunday, 1 for monday, etc....
so 2008W200 stands for the sunday of the 20th week of 2008.
This will only work in php 5 or better
rowe_a at glan-hafren dot ac dot uk
22-Aug-2008 11:16
22-Aug-2008 11:16
simple code to get the date of the monday and sunday of the current week.
inspired by: wulf dot kaiser at mpimf-heidelberg dot mpg dot de
<?
$day = date('d');
$wkday = date('l');
$month = date('m');
$year = date('Y');
switch($wkday) {
case 'Monday': $numDaysToSun = 6; $numDaysToMon = 0; break;
case 'Tuesday': $numDaysToSun = 5; $numDaysToMon = 1; break;
case 'Wednesday': $numDaysToSun = 4; $numDaysToMon = 2; break;
case 'Thursday': $numDaysToSun = 3; $numDaysToMon = 3; break;
case 'Friday': $numDaysToSun = 2; $numDaysToMon = 4; break;
case 'Saturday': $numDaysToSun = 1; $numDaysToMon = 5; break;
case 'Sunday': $numDaysToSun = 0; $numDaysToMon = 6; break;
}
echo $wkday;
echo " - ";
echo $day;
echo " - ";
echo $month;
echo " - ";
echo $year;
echo " - ";
echo $numDaysToSun;
echo " - ";
echo $numDaysToMon;
echo " - ";
echo $monday = date('d-m-Y', mktime('0','0','0', $month, $day-$numDaysToMon, $year));
echo " - ";
echo $sunday = date('d-m-Y', mktime('0','0','0', $month, $day+$numDaysToSun, $year));
?>
headings:
Day(string) - day - month - year - days to sun - days from mon - monday date - sunday date
output:
Friday - 22 - 08 - 2008 - 2 - 4 - 18-08-2008 - 24-08-2008
abazaba.ru
15-Aug-2008 12:53
15-Aug-2008 12:53
All novices must be very carefull when working with timestamps as second values.
From first glance it looks like date("Y-m-d H:i:s",TIMESTAMP) will return correct date, based on "how much seconds gone from 1970".
But here is the feature, it'll be corrected time, according to LOCAL timezone.
So if you take a 25200 as timestamp (10 hours),
then on one server you'll get
1970-01-01 08:00:00
and on other server you'll get
1970-01-01 09:00:00
and so on.
Though you could expect 1970-01-01 10:00:00 in all cases, because if 25200 seconds gone from 1970-01-01 00:00:00 it obviously have to be 1970-01-01 10:00:00
I spend today 3 hours to correct scripts which were created with such error by previous programmer, so please, guys, don't make me work like this and remember about conversation to LOCAL time.
phprocks at aol dot com
06-Aug-2008 08:25
06-Aug-2008 08:25
Try this for finding the difference in days between 2 dates/datetimes... take note though, date_parse requires PHP version 5.1.3 or higher.
<?php
/**
* Finds the difference in days between two calendar dates.
*
* @param Date $startDate
* @param Date $endDate
* @return Int
*/
function dateDiff($startDate, $endDate)
{
// Parse dates for conversion
$startArry = date_parse($startDate);
$endArry = date_parse($endDate);
// Convert dates to Julian Days
$start_date = gregoriantojd($startArry["month"], $startArry["day"], $startArry["year"]);
$end_date = gregoriantojd($endArry["month"], $endArry["day"], $endArry["year"]);
// Return difference
return round(($end_date - $start_date), 0);
}
?>
laszlo72 at gmail dot com
28-Jul-2008 12:16
28-Jul-2008 12:16
if you want to get the number of month
between two dates
you can use this function:
<?php
/*
$start = "YYYYMM" ;
$stop = "YYYYMM" ;
*/
function getNumMonth($start,$stop) {
$aSta = substr($start,0,4) ;
$aSto = substr($stop,0,4) ;
$mSta = substr($start,4,2) ;
$mSto = substr($stop,4,2) ;
if($aSta == $aSto) {
return $mSto-$mSta+1 ;
} else {
if(($aSto-$aSta) == 1) {
return 12-$mSta+$mSto+1 ;
} else {
return (12-$mSta+$mSto+1)+($aSto-$aSta-1)*12;
}
}
}
?>
JonathanCross.com
25-Jul-2008 10:22
25-Jul-2008 10:22
<?php
// A demonstration of the new DateTime class for those
// trying to use dates before 1970 or after 2038.
?>
<h2>PHP 2038 date bug demo (php version <?= phpversion() ?>)</h1>
<div style='float:left;margin-right:3em;'>
<h3>OLD Buggy date()</h3>
<?
$format='F j, Y';
for ( $i = 1900; $i < 2050; $i++) {
$datep = "$i-01-01";
?>
Trying: <?=$datep?> = <?=date($format, strtotime($datep))?><br>
<?
}
?></div>
<div style='float:left;'>
<h3>NEW DateTime Class (v 5.2+)</h3><?
for ( $i = 1900; $i < 2050; $i++) {
$datep = "$i-01-01";
$date = new DateTime($datep);
?>
Trying: <?=$datep?> = <?=$date->format($format)?><br>
<?
}
?></div>
gertrude dot mendoza at gmail dot com
18-Jul-2008 09:41
18-Jul-2008 09:41
<?php
/*
@params $firstdate, $lastdate
@return array() of array(monday,sunday)
@description returns all the mondays and sundays of the given date range
*/
function get_week_intervals($fdate,$ldate)
{
list($year,$month,$day) = explode('-',$fdate);
$daynum = date('w',
mktime(date('H'),
date('i'),
date('s'),
$month,
$day,
$year)
);
$daynum = $daynum==0? 7 : $daynum;
$week=array();
//get the dayname of the first day
//if month = current month get the current date as the last day
if($month==date('m'))
{
$lastday = date('d');
}
else
{
$lastday = date('t', strtotime($fdate));
}
if((date('l',strtotime($fdate))) == 'Sunday')
{
$monday = $fdate;
$sunday = $fdate;
}
else
{
$monday = $fdate;
$sunday = date('Y-m-d',(mktime(date('H'),
date('i'),date('s'),$month,
$day,$year))-($daynum-7)*86400);
}
$week[] = array('monday'=>$monday,'sunday'=>$sunday);
$day = date('d',strtotime($sunday." +1 day"));
while($sunday < $ldate)
{
$monday = date('Y-m-d',strtotime($sunday." +1 day"));
list($year,$month,$day) = explode('-',$monday);
$daynum = date('w',
mktime(date('H'),
date('i'),
date('s'),
$month,
$day,
$year)
);
$daynum = $daynum==0? 7 : $daynum;
$sunday = date('Y-m-d',(mktime(date('H'),date('i'),
date('s'),$month,$day,$year))-($daynum-7)*86400);
if($sunday > $ldate)
{
$sunday = $ldate;
}
$week[] = array('monday'=>$monday,'sunday'=>$sunday);
}
return $week;
}
?>
Anonymous
17-Jul-2008 06:30
17-Jul-2008 06:30
to get the date of the monday from a week these function is useful:
<?php
/* Get First Calendar Week of Year x*/
function firstkw($jahr)
{
$erster = mktime(0,0,0,1,1,$jahr);
$wtag = date('w',$erster);
if ($wtag <= 4) {
/**
* Donnerstag oder kleiner: auf den Montag zurückrechnen.
*/
$montag = mktime(0,0,0,1,1-($wtag-1),$jahr);
} else {
/**
* auf den Montag nach vorne rechnen.
*/
$montag = mktime(0,0,0,1,1+(7-$wtag+1),$jahr);
}
return $montag;
}
/*GET timestamp of monday of month x*/
function mondaykw($kwtime)
{
$firstmonday =$this->firstkw(date("Y", $kwtime));
$mon_monat = date('m',$firstmonday);
$mon_jahr = date('Y',$firstmonday);
$mon_tage = date('d',$firstmonday);
$tage = (date("W", $kwtime)-1)*7;
$mondaykw = mktime(0,0,0,$mon_monat,$mon_tage+$tage,$mon_jahr);
return $mondaykw;
}
echo mondaykw(time()); //1215986400
?>
fgabrieli at gmail dot com
14-Jul-2008 09:56
14-Jul-2008 09:56
here is a function to split a number of seconds in hours, minutes and seconds
<?php
function split_seconds($seconds)
{
// get the minutes
$minutes = floor($seconds / 60) ;
$seconds_left = $seconds % 60 ;
// get the hours
$hours = floor($minutes / 60) ;
$minutes_left = $minutes % 60 ;
// (test) show the result
echo "$hours hours $minutes_left minutes and $seconds_left seconds" ;
}
split_seconds(68648) ;
?>
best regards
fernando gabrieli
shem_lexluger at yahoo.com
14-Jul-2008 02:43
14-Jul-2008 02:43
Assuming a week starts on Monday. To calculate the week number of the current date starting from a specified date, use this function:
<?php
function weekcounter($start_date)
{
$start_date = strtotime($start_date);
$today = strtotime(date('d-m-Y'));
$week = 1;
while($start_date < $today) {
$start_date = strtotime('next Monday', $start_date);
$week++;
}
return $week;
}
// Example:
//now = 14-07-2008
echo weekcounter('01-07-2008'); //prints 3
echo weekcounter('01-06-2008'); //prints 8 instead of 7; because 1st jun is a Sunday so it is week 1 and 2nd june is week 2. Feel free to tweak.
?>
Rob A.
10-Jul-2008 06:38
10-Jul-2008 06:38
Quick function for returning the names of the next 7 days of the week starting with today.
Returns an array that can be formatted to your liking.
<?php
/**
* Returns array of next 7 days starting with today
*
*/
function next_7_days() {
// create array of day names. You can change these to whatever you want
$days = array(
'Monday',
'Tuesday',
'Wednesday',
'Thursday',
'Friday',
'Saturday',
'Sunday');
$today = date('N');
for ($i=1;$i<$today;$i++) {
// take the first element off the array
$shift = array_shift($days);
// ... and add it to the end of the array
array_push($days,$shift);
}
// returns the sorted array
return $days;
}
?>
It basically takes an array starting with Monday and shifts each day to the end of the array until the first element in the array is today.
con_tobe at yahoo dot com
10-Jul-2008 05:46
10-Jul-2008 05:46
Doing $w-- for months ending on Sat won't hurt (i.e. if you're counting weeks as is the case below), but halocastle's code is perfectly fine as is and quite fast. He/she uses $w as a key for the $weeks array. "Halo" does this BEFORE $w++, so $w-- is superfluous as the loop has already ended. For May, 2008, I get 5 weeks as expected...
Array
(
[1] => Array
(
[4] => 1
[5] => 2
[6] => 3
)
[2] => Array
(
[0] => 4
[1] => 5
------------OMITTED-----------------
[4] => 22
[5] => 23
[6] => 24
)
[5] => Array
(
[0] => 25
[1] => 26
[2] => 27
[3] => 28
[4] => 29
[5] => 30
[6] => 31
)
)
I guess the one pit-fall of the code is if you overlap months, say the following year, then $m-- makes perfect since...I think (haven't gotten that far...yet).
I modified "Halo's" code to include months, too (this is from a snippet that produces a three month calendar, hence the outer $months loop, omitted here).
<?php
$m = date('m');
$Y = date('Y');
// for() {months loop omitted
$var_date = mktime(0, 0, 0, $m, 1, $Y);
$month_name = date('F', $var_date);
$months[$month_name]['DAYS'] = date('t', $var_date);
$months[$month_name]['FIRST_DAY'] = date('w', $var_date);
//}
foreach($months as $month => $key) {
$weeks = array();
for($i = 1, $j = $key['FIRST_DAY'], $w = 1;$i <= $key['DAYS'];$i++) {
$weeks[$w][$j] = $i;
$j++;
if($j == 7) {
$j = 0;
$w++;
}
}
$months[$month]['WEEKS'] = $weeks;
}
?>
Enjoy!
dmagick at gmail dot com
03-Jul-2008 04:44
03-Jul-2008 04:44
Slight amendment to halocastle at yahoo dot com 's code as it doesn't take into account when a month finishes on a Saturday (eg May 2008).
<?php
$start_date = mktime(0, 0, 0,$start_month, 1, $start_year);
$days_in_month = date('t', $start_date);
$month_first_day = date('w', $start_date);
$j = $month_first_day;
$num_weeks = 1;
for($i = 1; $i <= $days_in_month; $i++) {
$j++;
if($j == 7) {
$j = 0;
$num_weeks++;
}
}
// if the last day of the month happens to be a Saturday,
// take one off the number of weeks
// because it was being added inside the for loop.
if ($j == 0) {
$num_weeks--;
}
?>
halocastle at yahoo dot com
01-Jul-2008 06:20
01-Jul-2008 06:20
Weeks and days for any month/year combo:
<?php
$m = 2; // February
$Y = 2008;
// constants used here for legibility, use $vars for dynamicon...
define('MONTH_DAYS',date('t', strtotime(date($m . '/01/' . $Y))));
// w:0->6 = Sun->Sat
define('MONTH_FIRST_DAY',date('w', strtotime(date($m . '/01/' . $Y))));
for($i = 1, $j = MONTH_FIRST_DAY, $w = 1;$i <= MONTH_DAYS;$i++) {
$week[$w][$j] = $i;
$j++;
if($j == 7) {
$j = 0;
$w++;
}
}
?>
print_r($week):
-----------------------
Array
(
[1] => Array
(
[5] => 1
[6] => 2
)
[2] => Array
(
[0] => 3
[1] => 4
[2] => 5
[3] => 6
[4] => 7
[5] => 8
[6] => 9
)
[3] => Array
(
[0] => 10
[1] => 11
[2] => 12
[3] => 13
[4] => 14
[5] => 15
[6] => 16
)
[4] => Array
(
[0] => 17
[1] => 18
[2] => 19
[3] => 20
[4] => 21
[5] => 22
[6] => 23
)
[5] => Array
(
[0] => 24
[1] => 25
[2] => 26
[3] => 27
[4] => 28
[5] => 29
)
)
Kavi Siegel
30-Jun-2008 04:18
30-Jun-2008 04:18
I wrote the following function to show a series of drop down boxes to select the date. When provided with a timestamp, that date is selected by default, when none is provided, the current date is selected.
<?php
function chooseDate($timestamp = ""){
if($timestamp == ""){
$timestamp = time();
}
$months = array(null, 'Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec');
unset($months[0]);
print_r($months);
$out = '<select name="month">';
foreach($months as $key => $month){
if($month == date('M', $timestamp)){
$out .= '<option value="'.$key.'" selected="selected">'.$month.'</option>';
}else{
$out .= '<option value="'.$key.'">'.$month.'</option>';
}
}
$out .= '</select><select name="days">';
for($i = 1; $i <= 32; $i++){
if($i == date('j', $timestamp)){
$out .= '<option value="'.$i.'" selected="selected">'.$i.'</option>';
}else{
$out .= '<option value="'.$i.'">'.$i.'</option>';
}
}
$out .= "</select><select name='year'>";
for($i = date('Y'); $i >= 1970; $i--){
if($i == date('Y', $timestamp)){
$out .= '<option value="'.$i.'" selected="selected">'.$i.'</option>';
}else{
$out .= '<option value="'.$i.'">'.$i.'</option>';
}
}
$out .= "</select>";
return $out;
}
?>
Usage is simple:
<?php
echo chooseDate(); // Will select current date
echo chooseDate(1149566400); // Will select June 6th, 2006
?>
aplarsen
26-Jun-2008 10:12
26-Jun-2008 10:12
@anonymous (12-Jun-2008 08:45):
date("t") returns the last day of the month, not the last working day of the month.
A cleaner example would be as follows:
<?php
function lastworkingday($date)
{
for($lastday=mktime(0,0,0,date("m",$date),
date("t",$date),date("Y",$date));
date("w",$lastday)==0 || date("w",$lastday)==6;
$lastday-=60*60*24);
return date("j",$lastday);
}
?>
kontakt at arthur minus schiwon dot de
18-Jun-2008 12:29
18-Jun-2008 12:29
to get the week of the month simply use:
ceil( date("j") / 7 );
diego at diego dot eng dot br
10-Jun-2008 01:27
10-Jun-2008 01:27
I made a small code to get the last working day of the month:
<?php
$times <